What you see, is what you get? (1.6x question)

Ghoste

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I don't know why I never thought about this question until now, but when you shoot digital and have the 1.6x zoom (Canons atleast), I'm guessing you have to guess what the picture is going to come out like since the sensor is seing the image close but the viewfinder is just seeing the normal lense length. Am I right? Just wondering, and if so how do you know where the viewfinder should be framing the picture? I hope I am making sense =p. Thanks guys.
 
Are you talking about the "crop factor" caused by the digital SLR's sensor? If so, it's not a "zoom" as you say, but just cropping of the edges of what a normal film lens would normally see. The viewfinder is already adjusted for this so that what you see is what you get.
 
the lens and viewfinder see approx the same. viewfinders approx 95% of the view. some top end cameras see 100%.

the 1.6x factor is for field of view and to convert to 35mm equiv
 

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