In my very first example I threw out your condition of fov being constant and introduced focal length as being constant, and guess what happens? Dof decreases with smaller sensors.
No need to guess, of course that's obvious. There is no point in comparing different photos. If you put a 165mm Angulon on an 8x10 camera and shoot the Grand Tetons that photo will have more DOF than a macro photo of a fly taken with a 165mm lens on a 35mm camera. Duh... so what.
The only comparison that makes any logical sense is to take the same photo.
Now this is not the whole story, just as your examples are not the whole story, but your thesis that smaller sensors produce greater dof does not hold true in all cases.
It's not a thesis it's proven and accepted fact. Here's a reference: "
'Same picture' for both formats
When the 'same picture' is taken in two different format sizes from the same distance at the same
f-number with lenses that give the same angle of view, and the final images (e.g., in prints, or on a projection screen or electronic display) are the same size, DOF is, to a first approximation, inversely proportional to format size (Stroebel 1976, 139)."
Depth of field - Wikipedia
Notice the reference to Stroebel. That would be Leslie Stroebel and his definitive text
View Camera Technique. I'm not going to type the whole paragraph so I took a snapshot (page 130 5th edition):
All I've been saying, and I think I've been quite clear about it, is that it's the use of shorter focal length lenses associated with smaller sensors and the use of smaller aperture diameters to maintain exposure, not the sensor size.
Chicken and egg argument and you're claiming the egg doesn't matter which is irrational.
I want to be able to say that the value of c changes with the size of the sensor
But you can't, because it doesn't.
Then you need to change the Wikipedia article on Circle of Confusion and get this chart out of there:
And then you need to contact Dan Fleming at DOFMaster and get him to remove this page:
Circles of Confusion for Digital Cameras Because they're changing the Coc value predicated on the size of the format.
c is not dof or sensor size it is the limit for the size of the coc and nothing else. You cannot equate something that is entirely derived from the optics as being a function of the sensor.
I never claimed Coc was a function of the sensor. I know better. I said that in an equation used to calculate DOF the value of Coc is selected predicated on the size of the recording media. I remain correct. I also said you can't find a DOF calculator that doesn't work that way. I posted this earlier:
Please note the two different values for Circle of confusion. They are different because the sensor sizes are different, an FX and DX camera. Please provide a link to an online DOF calculator that doesn't do that.
Smaller sensors actually have a negative effect on dof, they decrease it. It's only when you reduce the aperture diameter that dof increases, if you simply reduce sensor size and hold focal length and aperture constant then dof decreases with a smaller sensor.
1) If you have a set up where all you change is the camera body for one of a smaller sensor (the optics, exposure and subject distance remain the same), the dof decreases with the smaller sensor.
Two different photographs and so no comparison being made -- no meaning.
2) If you change the lens for a shorter focal length, (sensor size, exposure and subject distance remain the same), then dof increases.
Two different photographs and so no comparison being made -- no meaning.
Now if you do both, (change the sensor size to a smaller one and change the lens for one of a shorter focal length but maintain fov, subject distance and exposure constant), then the extra magnification needed for the smaller sensor decreases dof and the use of a shorter focal length (and the smaller aperture diameter to maintain exposure) increases it, but does so to a much larger extent.
Same photo and deeper DOF in the final print from the smaller sensor camera. Yep, that's what I've been saying.
The value of c does not change with sensor size,
In all equations used to calculate DOF the value of c is changed when the size of the sensor is changed. That's obvious from the screen shots above. Please provide a link to a DOF calculator that doesn't do that. That doesn't mean that Coc is a function of sensor size. It doesn't mean that sensor size alters the physics of optics. It simply means that we can't calculate DOF without a value that references the size of the sensor. An accommodation in the equation is made to account for the size of the sensor. Please provide a link to an online DOF calculator that doesn't do that.
Same hang-up, you're trying to calculate DOF at the sensor. It's not defined that way. You can't calculate DOF without including a value that is predicated in part on the size of the sensor. As such changing the size of the sensor changes the result of the calculation. Show us a calculator that doesn't do that.
Pragmatically one more time: Take the "same photo" with two cameras of different sensor size and the photo from the smaller sensor camera will have deeper DOF.
You just said that above and that's what I originally said, and the equations that are used to do that calculation include a value predicated on that sensor size. Show us a DOF calculator that doesn't do that.
I didn't say Coc is a function of sensor size. I didn't even say that Coc changes optically when we change the sensor size.
We change the value of Coc in the equations when we change sensor size. We get more accurate and practically useful results from the equations when we do that. We don't calculate DOF any other way --
can't calculate DOF without a value referenced to the sensor size and so sensor size is a DOF determinant.
Joe
it only changes with subject distance, f-stop and focal length, (or subject distance and aperture diameter, but please note that to maintain exposure it is much better to use f-stop and therefore it is subject distance, f-stop and focal length). The only effect sensor size has is in the magnification to the final reference print, and smaller sensors need greater magnification.
I cannot be clearer.