FocusTester
TPF Noob!
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- Dec 29, 2013
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I know that when a full frame lens is mounted on an APS-C camera, the focal length should be multiplied by 1.6 to find the full-frame equivalent focal length. Likewise, it is often said that the aperture value should be multiplied by 1.6 as well.
Therefore, a 100/2.8 lens effectively becomes 160/4.2 when mounted on an APS-C camera. I understand this with regard to effective magnification and extension of the depth of field, but is there really a stop of light loss when this lens is used on an APS-C camera. Having the aperture shift from 2.8 to an effective 4.2 would seem to indicate this, but it is hard to believe. After all, the same amount of light is going through the lens.
Maybe the implication is that the 4.2 aperture affects the depth of field only, without there being a stop of light loss. In other words, you still get the speed of a f/2.8 lens but the depth of field of a f/4.2 lens.
Can someone please clarify this.
Therefore, a 100/2.8 lens effectively becomes 160/4.2 when mounted on an APS-C camera. I understand this with regard to effective magnification and extension of the depth of field, but is there really a stop of light loss when this lens is used on an APS-C camera. Having the aperture shift from 2.8 to an effective 4.2 would seem to indicate this, but it is hard to believe. After all, the same amount of light is going through the lens.
Maybe the implication is that the 4.2 aperture affects the depth of field only, without there being a stop of light loss. In other words, you still get the speed of a f/2.8 lens but the depth of field of a f/4.2 lens.
Can someone please clarify this.