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Iron Flatline
Guest
No, lemme see if I can explain that.Lets think about it in terms of the size of the movement. Lets say that the camera/lens shakes 1/16" during exposure. That is a small fraction, compared to the size of a 2.5x2.5 negative...but it's comparatively a much bigger movement to a APS-C sensor. So would that movement cause more of an effect on the smaller surface? Does that argument have any validity?
Let's say the camera shake is a pencil mark on a piece of paper. In this case the pencil mark will still be a quarter inch long, regardless of whether the piece of paper 8.5x11 inches big, or 13x19 inches.
It is not comparatively a much bigger movement - it is the exact same movement!
In the case of camera shake, the piece of film or sensor at the end has no meaning to what is happening to the light on the way into and through the camera - just how big an area of the whole image is ultimately recorded.