What's new

Anyone keen to photograph some candles, for scientific experiment?

Status
Not open for further replies.
You failed to articulate yourself. What are you doing, trying to outsmart me or something? Don't you have anything better to do? -- The only thing that was not mention and does not relate to brightness is 'gravitational lenses', which is terribly uncertain method.

OK, if brightness is the only method that works for 'everything else', why won't it work for everything? Why bother with parallax for all the close stuff?

And there's more methods used to establish distances that what has been mentioned in this thread.
 
The brightness of the image also depends on the area of the image. Half the photons, half the area: same image brightness. If using an image of the candles you need to take the image area into account. As I said, you need to integrate the brightness of the elements that make up the image.

Right. It's just that no one was able to point any reference about how inverse square law relates to apparent size. Can you point some reference about it maybe? Wikipedia doesn't seem to be aware of it:

Inverse-square law - Wikipedia, the free encyclopedia

de6ee5f95f4bd85100de8d126060c87c.png



It's not part of the equation. So how do you know, where do you pull your conclusions from?
 
^^ in other words, brightness is photon density over space. You could have all the photons of a very bright star beaming down onto a our retna, enough energy to instantly vaporize a hole through our head, or likewise, you could have all that energy distributed over such a large area that with only a few photons would ever enter our eye's aperture, making it entirely invisible. Regardless, the star emitted the same number of photons over any given time period, all that has changed is the density: it's brightness.

Go read Helen's comments on the link I provided, it discusses how light is focussed proportional to it's apparent brightness.

It's important to note that the nature of light isn't what we're seeing, and that our perception of things is based on focused light. In some ways, a sheet of exposed film left out on the table is more "accurate" than one behind a lens. Of course, we can't really make much sense of this.
 
You failed to articulate yourself. What are you doing, trying to outsmart me or something? Don't you have anything better to do? -- The only thing that was not mention and does not relate to brightness is 'gravitational lenses', which is terribly uncertain method.

OK, if brightness is the only method that works for 'everything else', why won't it work for everything? Why bother with parallax for all the close stuff?

And there's more methods used to establish distances that what has been mentioned in this thread.

I have no idea what are we arguing about. Majority of methods are based on reading brightness, one way or another. Parallax is limited to nearby stars. That's all I said. Why bother with parallax? It offers more certainty, as far it is works, since 'standard candle' methods depend on some reference stars, like supernovas, and that by itself brings uncertainty into equation. -- Can you now take a camera and snap a few photos of some candles for me? I'll pay you, say $40 bucks, how about it?
 
Why would image size be mentioned in a discussion of the inverse square law, unless the brightness of an image was under consideration. Where do I draw my conclusion that the image area exactly compensates for the inverse square law? It is fundamental, simple optics. I'm amazed that you question it. If you have two identical objects, one 10 distance units away and the other 20 distance units away, what do you think the ratio of the image areas will be (assuming that they are being imaged by the same system, and before considering focus effects)?
 
Why would image size be mentioned in a discussion of the inverse square law, unless the brightness of an image was under consideration. Where do I draw my conclusion that the image area exactly compensates for the inverse square law? It is fundamental, simple optics. I'm amazed that you question it. If you have two identical objects, one 10 distance units away and the other 20 distance units away, what do you think the ratio of the image areas will be (assuming that they are being imaged by the same system, and before considering focus effects)?

I thought this thread was closed. Can we then continue our discussion here? -- We got so close to come to agreement. People were misunderstanding me thinking I was talking about my theory, but I stopped talking about it few days ago and I just wanted to establish the basics.
 
Why would image size be mentioned in a discussion of the inverse square law, unless the brightness of an image was under consideration. Where do I draw my conclusion that the image area exactly compensates for the inverse square law? It is fundamental, simple optics. I'm amazed that you question it. If you have two identical objects, one 10 distance units away and the other 20 distance units away, what do you think the ratio of the image areas will be (assuming that they are being imaged by the same system, and before considering focus effects)?

I thought this thread was closed. Can we then continue our discussion here? -- We got so close to come to agreement. People were misunderstanding me thinking I was talking about my theory, but I stopped talking about it few days ago and I just wanted to establish the basics.

what needs to be discussed still? I gave you the pictures you asked for. We've given you multiple explanations for why this is the case. What more do you want?
 
I'm not worked up about it, just generally confused about what is left to discuss. The inverse square law has been completely understood for over 1000 years now. The principals in the thread understand it. If you can't figure out what else you're confused about, I'm not sure what is left to discuss. I'm genuinely trying to help you with this, I'm a teacher, so I understand that sometimes students require multiple explanations to get something, but I don't even know what you're looking for any longer. I don't really have an interest in joining the conversation about this, other than I enjoy teaching and figuring out new ways to explain things to people who don't get them. Outside of that, I don't know what discussion there is left to have.
 
I am not arguing my theory, just trying to establish the facts. We now agree on great many things, I just want to clear it up a bit more and summarize it. Then I would like to apply what we have established to some practical examples in order gain complete understanding. Let me gather the stuff from the other thread and I'll put forward a few questions.
 
fjrabon said:
As you can see, the 'blob' gets bigger, as the light gets dimmer.

What this doesn't mean was that if I was to look at the lamp directly that the actual lamp itself would appear dimmer. It's that the total light falling on my eye would be less, because it's coming from a smaller part of my visual frame, due to how our eyes focus. Once you take focus out of the equation, further light sources are actually in some sense bigger the further they are.

Sources of light that radiate photons radially, such as point or a spherical light source, without lens would imprint bigger blob on a photo as distance increases, and the brightness of the pixel in the center of that blob would become less bright proportionally to the square of the distance. Ok?


Consider what Isaac said:
- "If you have a spherical light source (like one of those oriental paper lanterns), it still follows the inverse square law no matter how close you are to it. You can think of this as a quirk peculiar to spheres."

Does what he said not mean if we photograph such spherical light source it will produce less bright blob on the image proportionally to the square of the distance, as if it was a point light source?

No, because you're optically altering the light due to having a lens in front of it. You're taking all that dispersed light and then recombining it into a smaller light, of equal brightness. Which is why we kept telling you all along that you can represent the falloff as the light sources being dimmer, or smaller, BUT NOT BOTH.

As light source gets further away its projected blob without lens gets bigger, so even when there is a lens with longer distance more light would just fly around it and miss the lens, so should we therefore not expect that brightness would fall off with the distance even when there is a lens because lens would proportionally receive less light as the distance increases?
 
Sources of light that radiate photons radially, such as point or a spherical light source, without lens would imprint bigger blob on a photo as distance increases, and the brightness of the pixel in the center of that blob would become less bright proportionally to the square of the distance. Ok?

No. "imprint a blob" is a meaningless phrase in this context. What you have said is, as scientists say "not even wrong"

As light source gets further away its projected blob without lens gets bigger, so even when there is a lens lots of light would just fly around it and miss the lens, so should we therefore not expect that brightness would fall off with the distance even when there is a lens because lens would proportionally receive less light as the distance increases?

No, we should not expect the brightness to fall off. The job of the lens in this context can be viewed as gathering up that proportionally smaller amount of light, and using it to render an image on the sensor that is proportionally smaller, and equally as bright. We photographers call this "focusing".
 
As light source gets further away its projected blob without lens gets bigger, so even when there is a lens with longer distance more light would just fly around it and miss the lens, so should we therefore not expect that brightness would fall off with the distance even when there is a lens because lens would proportionally receive less light as the distance increases?

Need a little more paint, partnah?
 
fjrabon said:
As you can see, the 'blob' gets bigger, as the light gets dimmer.

What this doesn't mean was that if I was to look at the lamp directly that the actual lamp itself would appear dimmer. It's that the total light falling on my eye would be less, because it's coming from a smaller part of my visual frame, due to how our eyes focus. Once you take focus out of the equation, further light sources are actually in some sense bigger the further they are.

Sources of light that radiate photons radially, such as point or a spherical light source, without lens would imprint bigger blob on a photo as distance increases, and the brightness of the pixel in the center of that blob would become less bright proportionally to the square of the distance. Ok?


Consider what Isaac said:
- "If you have a spherical light source (like one of those oriental paper lanterns), it still follows the inverse square law no matter how close you are to it. You can think of this as a quirk peculiar to spheres."

Does what he said not mean if we photograph such spherical light source it will produce less bright blob on the image proportionally to the square of the distance, as if it was a point light source?

No, because you're optically altering the light due to having a lens in front of it. You're taking all that dispersed light and then recombining it into a smaller light, of equal brightness. Which is why we kept telling you all along that you can represent the falloff as the light sources being dimmer, or smaller, BUT NOT BOTH.

As light source gets further away its projected blob without lens gets bigger, so even when there is a lens lots of light would just fly around it and miss the lens, so should we therefore not expect that brightness would fall off with the distance even when there is a lens because lens would proportionally receive less light as the distance increases?

You seem to be confusing light fields and points of light as resolved by a lens or an eye.

Lenses take light from a source that is hitting your eye, all across retina, and focuses it into a coherent image. When you look at a candle, the light from that candle isn't hitting a small part of your eye, its hitting your whole eye, your whole body, the whole room. Your eye focuses it. Whatever size the flame looks like is based upon your distance to it, as the further you move away, the smaller part of your visual frame it takes up. However, because your eye (or camera) focused the diffuse light back into a coherent image, you no longer get the dimming effect. Your eye sees the candle as brightly as it would see it a few feet away.

So, if you focus the light you get the smaller effect, but not the dimmer effect. If you were not to focus the light (essentially what holding a sheet of paper over the light does) you would get the dimming effect, but a corresponding increase in the 'spread' of the light (which is the whole reason the inverse square law works to begin with).

This is why we kept telling you that you could represent stars as dimming, or getting smaller, but not both.

The reason why stars appear to get dimmer the further they get is because they are too far away for our eyes to focus on them. We can only focus at an arbitrarily far point into space, and after that, things just look equally small. Because we can't really focus on the objects in space, as they get further away, they simply look dimmer. If, however, you had a telescope accurate enough to focus on them, they would look just as bright as anything else, even if they were very tiny.

Now, measuring the amount of light falling on an area from a light is a totally different matter. If you're in a dark room and you have a light meter, as you move a flash light closer to the light meter, it will register more light. As you move it away, it will register less. However, if you took pictures of the same flashlight, the actual flashlight would seem equally as bright no matter the distance. However, in the further picture it would be taking up less space in the visual frame. What that means is that if you were to calculate the value the sensor read for the flashlight and multiply it by the area it took up in the frame, the flashlight that was further away would follow the rules of the inverse square law, because the less light is being illustrated by the light taking up less space in the frame.

again, indicating that you can illustrate the inverse square law as lights being dimmer, or lights being smaller, but not both. Which was your original problem.
 
christop, I acknowledge what you said in that other thread, ASCII stuff and all that. I addressed it with the question to fjrabon in my previous post.


Helen B said:
E = t π B / (4 N^2)

Where
E is the image illumination,
t is the lens transmittance (dimensionless),
π is Pi (dimensionless),
B is the object illumination, and
N is the f-number (dimensionless).

Note the absence of any term relating to the distance to the object.

The above equation does not contradict the inverse square law at all.

It's not that it contradicts, the question is whether it has anything to do with inverse square law, which is all about the distance.
 
Status
Not open for further replies.
Back
Top Bottom