Oh god. Don't say that! I cannot tell you how much I HATE Peterson!
However, I disagree that QY/QE should be excluded; and I recognize that the accepted definition disagrees. And I am OK with that.
As another example. Take two sensors, one with a base equivalent ISO of 800 and another with an equivalent ISO of 200. Now, we set these two sensors and expose the same quantity of light to both. Without attenuation, will both sensors result in the same measured data?
While it is arguable that the ISO 800 sensor is more efficient, wasting fewer electrons than the ISO 200 sensor, and likewise more accurate to the actual quantity of photons, because without the higher sensitive sensor we'd have no means to account for them, thus making it irrelevant. Likewise without a sensor with 100% QE, the task of knowing the exact number of photons (and thus the exact number of photons lost) in any given space (using the output of the sensor alone) would be impossible!
Excluding the photo- chemical/electric properties of the medium doesn't really make sense to me. Exposure without a medium is like calling light traveling through a vacuum an exposure. At any given plane within this space there is some quantity of light, but we have no idea what that quantity is until there is something for the light to interact with. The knowledge that there is a quantity of light itself has no meaning.
Perhaps gain could be excluded since this is a process of feeding current back through an amplifier and has nothing to do with the photoelectric reaction, though this is splitting hairs.