The impossible math problem...

[Corry]

Nerd to the 3rd power.

I have nothing more to say to you. You're now a lost cause.

 

[MommyOf4Boys]

:cry:

 

[monicam]

CORRECTION:

x = |t - 1|
x = |(-3) - 1|
x = |(-4)|
x = 4

t = x - 1
t = (4) - 1
t = -3

-3 = -3

 

[Unimaxium]

Finally you get it!

Not so impossible after all, eh?

 

[monicam]

Finally you get it!

Not so impossible after all, eh?

ahahahaha..:lmao:

 

[Rob]

 

[MommyOf4Boys]

ROFLMAO ROB!

 

[nvr2low]

haha, nice. no more posting about Fourier Transforms, i had enough of those in calc and diff eq. i dont want to see them ever again. you want a near imposible problem, one of the engineers i work with says he can algebracily prove that 2=1. figure that out and i will give you a star.

 

[hot shot]

This really is simple algebra

i hope the smarmy git is band by this point

 

[Corry]

i hope the smarmy git is band by this point

Uni in the Sky? Banned? NEVER!!!

 

[mentos_007]

That is impossible. You have two variables, and only one equation, so there can be no single answer. However, we can say that:
t=1-x and t=1+x

Now find me the square root of -1.

haha and what about compounds (dunno if this is a proper word) where sqrt(-1)=i
there you have imaginary axis (y) and real (x)

 

[Unimaxium]

now figure out why e^(pi*i) = -1

 

[Unimaxium]

oh, and the proof that 1=2

say a = b
a^2 = ab
a^2 + (a^2 - 2ab) = ab + (a^2 - 2ab)
2(a^2 - ab) = 1 (a^2 - ab)
2 = 1

actually there's a problem in that proof. now see if you can figure out what it is. and joe and company, no spoiling the answer for others!

 

[nvr2low]

how did you get 2 outside on 2(a^2-2ab). i follow up to that point but i cant think how you how you do it. if you simplify

a^2 + (a^2 - 2ab) = ab + (a^2 - 2ab)

you should get

(a^2-2ab) = (a^2-2ab)

right?

you bring a^2 over and subtract out?

so how do you go from that to

2(a^2 - ab) = 1 (a^2 - ab)

how did you get 2 out of 1 and 1 out of the other? im stumped right there.

 

[clarinetJWD]

actually there's a problem in that proof. now see if you can figure out what it is. and joe and company, no spoiling the answer for others!

My friend has a T-shirt with that on it....